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5 Click New again and overtype Group 2 with Expensive 6 Select your newly created group, Value Then select the prices on the left that are < $100 and click Add 7 Repeat this to add items > $100 to the Expensive group 8 Click OK to close the New Variable dialog and Close to close the Variables dialog 9 Insert an additional column in your report with the new grouping variable, Price Category

Sometimes you will want to remove leading and trailing spaces from a string This type of operation, called trimming, is often needed by command processors For example, a database might recognize the word print However, a user might enter this command with one or more leading or trailing spaces Any such spaces must be removed before the string can be recognized by the database Conversely, sometimes you will want to pad a string with spaces so that it meets some minimal length For example, if you are preparing formatted output, you might need to ensure that each line is a certain length in order to maintain an alignment Fortunately, C# includes methods that make these types of operations easy To trim a string, use one of these Trim( ) methods: public string Trim( ) public string Trim(params char[ ] trimChars) The first form removes leading and trailing whitespace from the invoking string The second form removes leading and trailing occurrences of the characters specified by trimChars In both cases, the resulting string is returned You can pad a string by adding characters to either the left or the right side of the string To pad a string on the left, use one of the methods shown here: public string PadLeft(int totalWidth) public string PadLeft(int totalWidth, char paddingChar) The first form adds spaces on the left as needed to the invoking string so that its total length equals totalWidth The second form adds the character specified by paddingChar as needed to the invoking string so that its total length equals totalWidth In both cases, the resulting string is returned If totalWidth is less than the length of the invoking string, a copy of the invoking string is returned unaltered To pad a string to the right, use one of these methods: public string PadRight(int totalWidth) public string PadRight(int totalWidth, char paddingChar).

designer For instance, selection of the collocation points is readily automated Such operations are described in the example, however, for the sake of thoroughness

TIP For groups that are based on values from measures, consider creating a variable that uses ifthen-else statements and ranges to provide more flexible definitions

Part II:

The first form adds spaces on the right as needed to the invoking string so that its total length equals totalWidth The second form adds the characters specified by paddingChar as needed to the invoking string so that its total length equals totalWidth In both cases, the resulting string is returned If totalWidth is less than the length of the invoking string, a copy of the invoking string is returned unaltered The following program demonstrates trimming and padding:

Synthesis of the Output Motion In this illustration the basic goal is to satisfy the ten basic constraints at t = 0 and at t = 1 in the list of constraints that follows These constraints are the primary design constraints The two additional constraints at t = 05 were added in the iterative process to re ne the motion somewhat Since the degree of the spline curve is k - 1, splines of order k = 6 are required for S(4) to be continuous It is necessary to achieve this continuity if the constraints on S(4) are to be satis ed, as they must be if continuous cam acceleration is to be obtained The output motion that is synthesized using spline functions is shown in Figures 524 to 528 and compared to the motion produced by the optimized polynomial Collocation Solution of the Differential Equations To solve the differential Eqs (518) and (531) for the cam displacements and for vibrational responses, the normalized time domain (t) is divided into sixteen equal elements (e = 16) and in each element four Gaussian points (p = 4) are located Both the number of elements used and the choice of